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Your Name committed 2026-11-01 01:59:35 +08:00
1 parent 9362c48811
commit bbc2a605d4
3 files changed
+133 -5

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+104
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@@ -0,0 +1,104 @@
#include<bits/stdc++.h>
using namespace std;
int c, t;
int n, k;
vector<int> fri[1000005];
int fa[1000005];
int son[1000005];
int cnt[1000005];
int top[1000005];
int dep[1000005];
int depmaxson[1000005];
void dfs1(int now, int from) {
cnt[now] = 1;
depmaxson[now] = dep[now];
for(int i : fri[now]) {
if(i == from) continue;
fa[i] = now;
dep[i] = dep[now] + 1;
dfs1(i, now);
depmaxson[now] = max(depmaxson[now], depmaxson[i]);
cnt[now] += cnt[i];
if(cnt[son[now]] < cnt[i]) son[now] = i;
}
}
void dfs2(int now, int from) {
top[now] = from;
if(son[now]) dfs2(son[now], from);
for(int i : fri[now]) {
if(i == fa[now] || i == son[now]) continue;
dfs2(i, i);
}
}
int lca(int a, int b) {
while(top[a] != top[b]) {
if(dep[top[a]] < dep[top[b]]) swap(a, b);
a = fa[top[a]];
}
if(dep[a] < dep[b]) swap(a, b);
return b;
}
bool chosen[1000005];
struct BCJ{
int fa[1000005];
int find(int x) {
if(fa[x] == x) return x;
return fa[x] = find(fa[x]);
}
}bcj;
void dfs0(int now) {
for(int i : fri[now]) {
if(i == fa[now]) continue;
if(chosen[i] && chosen[now]) bcj.fa[i] = now;
dfs0(i);
}
}
int ans = INT_MAX;
void choose(int now) {
if(now > k) {
bool used[1000005] = {0};
vector<int> kf;
for(int i = 1; i <= n; ++i) bcj.fa[i] = i;
dfs0(1);
int cnt = 0;
for(int i = 1; i <= n; ++i) {
if(!used[bcj.find(i)]) used[bcj.find(i)] = 1, cnt++, kf.push_back(bcj.find(i));
if(cnt > 2) return;
}
int l = lca(kf[0], kf[1]);
ans = min(ans, depmaxson[kf[0]] + depmaxson[kf[1]] - 2 * dep[l]);
}
for(int i = 1; i <= n; ++i) {
if(!chosen[i]) chosen[i] = 1, choose(now + 1), chosen[i] = 0;
}
}
int main() {
freopen("hub.in", "r", stdin);
freopen("hub.out", "w", stdout);
scanf("%d%d", &c, &t);
while(t--) {
scanf("%d%d", &n, &k);
for(int i = 1, u, v; i < n; ++i) {
scanf("%d%d", &u, &v);
fri[u].push_back(v);
fri[v].push_back(u);
}
if(k == n) {
printf("0\n");
for(int i = 1; i <= n; ++i) fri[i].clear();
}
dfs1(1, 1);
dfs2(1, 1);
choose(1);
printf("%d\n", ans);
for(int i = 1; i <= n; ++i) fri[i].clear();
ans = INT_MAX;
}
return 0;
}
/*
g++ hub/hub.cpp -o hub/hub -std=c++14 -O2 -static -Wall && cp hub/hub ~ && chmod +x ~/hub && ~/hub
对于两个连通块中的点,距离为道路条数(lca)
*/
+25 -4
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@@ -1,16 +1,36 @@
#include<bits/stdc++.h> #include<bits/stdc++.h>
using namespace std; using namespace std;
int c, t; int c, t;
int n, d; int n;
int x[2000005]; long long d;
long long x[2000005];
long long fa[5005][5005];
int main() { int main() {
freopen("migrate.in", "r", stdin); freopen("migrate.in", "r", stdin);
freopen("migrate.out", "w", stdout); freopen("migrate.out", "w", stdout);
scanf("%d%d", &c, &t); scanf("%d%d", &c, &t);
while(t--) { while(t--) {
scanf("%d%d", &n, &d); scanf("%d%lld", &n, &d);
for(int i = 1; i <= n; ++i) { for(int i = 1; i <= n; ++i) {
scanf("%d", &x[i]); scanf("%lld", &x[i]);
}
if(c <= 10) {
long long ans = 0;
for(int i = 1; i < n; ++i) {
fa[i][i] = 1;
fa[i][i + 1] = (x[i + 1] - x[i] <= d) && (fa[x + 2] - x[i]) > d;
}
fa[n][n] = 1;
for(int len = 2; len <= n; ++len) {
for(int l = 1; l + len - 1 <= n; ++l) {
int r = l + len - 1;
for(int mid = l; mid <= r - 1; ++mid) {
fa[l][r] += fa[l][mid] * fa[mid + 1][r];
}
if(fa[l][r] == 2) ans++;
}
}
printf("%lld\n", ans);
} }
} }
return 0; return 0;
@@ -20,4 +40,5 @@ g++ migrate/migrate.cpp -o migrate/migrate -std=c++14 -O2 -static -Wall && cp mi
每次飞行长度不超过 d 每次飞行长度不超过 d
体力消耗为飞行次数 体力消耗为飞行次数
长度最短一定不回溯
*/ */
+4 -1
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@@ -55,7 +55,8 @@ int main() {
} }
} }
// dig(x); // dig(x);
printf("%lld\n", 1ll * w[x] + 1ll * w[y] + ans); if(ans == LLONG_MAX) printf("-1\n"); // 疑似算法有问题
else printf("%lld\n", 1ll * w[x] + 1ll * w[y] + ans);
} }
return 0; return 0;
} }
@@ -66,4 +67,6 @@ g++ subway/subway.cpp -o subway/subway -std=c++14 -O2 -static -Wall && cp subway
500 条线路各视为图上的一个点,分别和地铁站连线 500 条线路各视为图上的一个点,分别和地铁站连线
考虑优化,注意到可以预处理维护两个地铁线路的最短距离,再枚举起点终点的线路选择 考虑优化,注意到可以预处理维护两个地铁线路的最短距离,再枚举起点终点的线路选择
爆longlong得到负值(原因为数据构造器未保证连通)
*/ */